Topic: I can't seem to grasp the concept of mathematics
+2+9=29 — 4.6 years ago #60,683
How does mathematics work? Or in a simpler terms, addition. How does addition work?
+Anonymous B — 4.6 years ago, 3 minutes later[T] [B] #618,154
·Anonymous A (OP) — 4.6 years ago, 20 minutes later, 23 minutes after the original post[T] [B] #618,155
+Anonymous C — 4.6 years ago, 12 minutes later, 36 minutes after the original post[T] [B] #618,156
@OP
That's wonderful, sweetie.
That's wonderful, sweetie.
+Anonymous D — 4.6 years ago, 4 hours later, 5 hours after the original post[T] [B] #618,169
you need to go back to 1st grade
·Anonymous A (OP) — 4.6 years ago, 32 minutes later, 6 hours after the original post[T] [B] #618,171
@previous (D)
Who, me? Nah... I graduated 1st grade nearly 26 years ago. Yikes, you're reminding me how old I'm getting. I think I should repeat 4th grade and up. I can't remember anything I learned after those years.
Who, me? Nah... I graduated 1st grade nearly 26 years ago. Yikes, you're reminding me how old I'm getting. I think I should repeat 4th grade and up. I can't remember anything I learned after those years.
+Anonymous E — 4.6 years ago, 20 minutes later, 6 hours after the original post[T] [B] #618,173
@OP
Confirmed for retard.
Confirmed for retard.
·2+9=29 (OP) — 4.6 years ago, 2 hours later, 8 hours after the original post[T] [B] #618,178
@previous (E)
> Confirmed for retard.
No I ain't. I just have trouble with math. Everything else is easy peasy.
> Confirmed for retard.
No I ain't. I just have trouble with math. Everything else is easy peasy.
·Anonymous D — 4.6 years ago, 4 hours later, 12 hours after the original post[T] [B] #618,185
@618,171 (A)So by your understanding of math, (2+9=29) you graduated 1st grade 26 years ago?
So 2+6=26 to you. 2+6 is actually 8. So in fact, you graduated 1st grade 8 years ago. That puts you in 9th grade now. That means you're in high school (at least in areas with 4-year high schools). Generally you're required to have turned 5 years old by the first day of Kindergarten, meaning you'd be 6 when you start 1st grade. 6+9 is actually 15. TC's rules state that you must be 18 years of age to use this site. You've been outed as underage and I'll be reporting you for violating that rule.
But before you get banned,
> I graduated 1st grade
lmfao you're such a special snowflake. Did you get a diploma too?
PS: This file has been on TC longer than you've been in school ffs
(Edited 4 minutes later.)
·Anonymous E — 4.6 years ago, 2 hours later, 15 hours after the original post[T] [B] #618,189
·2+9=29 (OP) — 4.6 years ago, 3 hours later, 18 hours after the original post[T] [B] #618,192
@618,185 (D)
Hey, calm down. I can't believe I read all of that but I can clearly see that you're thinking too hard about this whole thing.
Hey, calm down. I can't believe I read all of that but I can clearly see that you're thinking too hard about this whole thing.
(Edited 21 seconds later.)
+Anonymous F — 4.6 years ago, 4 minutes later, 18 hours after the original post[T] [B] #618,193
@618,189 (E)
> Don't yell at the first grader.
I agree. We don't need a first grader pooping his pants and crying for mommy.
> Don't yell at the first grader.
I agree. We don't need a first grader pooping his pants and crying for mommy.
+Anonymous G — 4.6 years ago, 4 minutes later, 18 hours after the original post[T] [B] #618,194
One of the best example to make math fun is to learn how to calculate boobs' size. 🍑·Anonymous F — 4.6 years ago, 26 minutes later, 19 hours after the original post[T] [B] #618,195
@previous (G)
Fuck the boob size, I wanna learn math by counting how many times I have to lick her clit until she cums.
Fuck the boob size, I wanna learn math by counting how many times I have to lick her clit until she cums.
+Anonymous H — 4.6 years ago, 6 days later, 1 week after the original post[T] [B] #618,565
If you are left handed, maybe you will be better at maths! ⚡ http://www.zmescience.com/science/math/left-hand-math-09052016
·Anonymous A (OP) — 4.6 years ago, 8 hours later, 1 week after the original post[T] [B] #618,579
@previous (H)
I think I am ambidextrous because I write with my left hand and do everything else with my right hand.
I think I am ambidextrous because I write with my left hand and do everything else with my right hand.
+Anonymous I — 4.1 years ago, 5 months later, 6 months after the original post[T] [B] #626,568
Join the right math community help improve your maths. http://www.fosteringmathpractices.com
·Anonymous D — 4.1 years ago, 7 hours later, 6 months after the original post[T] [B] #626,585
@618,189 (E)
Ok, I'll help by posting a cheat sheet I compiled a decade ago.
> Straight lines as in completely vertical or completely horizontal are either y=some number or x=some number. Any horizontal line is of the y=some number variety and any vertical line is of the x=some number variety. This can be derived from the slope intercept form of graphing, which is
> To determine an equation from a graph there are two approaches. If the line is completely vertical or horizontal and only crosses one axis then determine where it crosses and you have your answer of either
> You can check yourself by making a table, plugging in numbers for x and then getting an answer for y. After you have three or four coordinates, graph them and it should match the line from the original graph.
i 1 = i
i 2 = -1
i 3 = -i [i*i2 = (-1)i]
i 4 = 1
h=vertex(x)
k=vertex(y)
[h]x=-b/2a
a>0=opens up
a<0=opens down
y=a(x-h)2+k
Ok, I'll help by posting a cheat sheet I compiled a decade ago.
Slopes
> Straight lines as in completely vertical or completely horizontal are either y=some number or x=some number. Any horizontal line is of the y=some number variety and any vertical line is of the x=some number variety. This can be derived from the slope intercept form of graphing, which is
y=mx+b. The "m" is generally the slope of the line and the "b" is where the line will cross the y-axis.
> To determine an equation from a graph there are two approaches. If the line is completely vertical or horizontal and only crosses one axis then determine where it crosses and you have your answer of either
y=aor
x=b(depending on the line). For other linear examples you can use the slope intercept form as reference (
y=mx+b).
bwill be where the line crosses the y-axis and
mcan be determined using the point-slope formula {
(y-y1)/(x-x1)x cannot equal zero}. To use the point-slope pick two numbers where the line crosses the y-axis, subtract them and divide them by the difference of two numbers where the line crosses the x-axis. You then plug m and b into the y=mx+b formula and you have your answer.
> You can check yourself by making a table, plugging in numbers for x and then getting an answer for y. After you have three or four coordinates, graph them and it should match the line from the original graph.
- vertical slopes are undefined
- leading coefficient corresponds to whatever is attached to the higest degree (power)
Linear inequalities
- for > or < graph is dashed
- shade the true region
- for > or < use () on the number
- for ≥ use [)
- for ≤ use (]
- domain is horizontal (x axis)
- range is vertical (y axis)
- for vertical graphs, domain is in {}
- ∞ solutions = dependant (same)
- 1 solution = consistent (intersection)
- no solution = inconsistent (parallel)
Squares, Cubes and Roots
1 1 2 3 4 5 6 7 8 9 10
2 1 4 9 16 25 36 42 64 81 100
3 1 8 27 64 125 216 343 512 749 1000
Compound Interest
n= for term
1 annually
2 semi-annually
4 quarterly
12 monthly
Logs
- base refers to number being squared, cubed, etc.
- for ex use
ln
, otherwise use log
Exp. form <=> Log. form
32=9 <=> log2(9)=2
2 log(x) <=> log(x2)
- to solve 3x=9 do log(9)/log(3)
Radicands and Imaginary Numbers
i 0 = 1i 1 = i
i 2 = -1
i 3 = -i [i*i2 = (-1)i]
i 4 = 1
Quadratic Formulas
(-b±√(b2-4ac))/2ah=vertex(x)
k=vertex(y)
[h]x=-b/2a
a>0=opens up
a<0=opens down
y=a(x-h)2+k
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