Topic: Question of the day.
+Anonymous A — 11.4 years ago #41,256
Among 45 people, must there be 5 mutual strangers or 5 mutual acquaintances?
Can you prove this to be true?
+Anonymous B — 11.4 years ago, 32 minutes later[T] [B] #449,936
Yes and yes to both questions.
+The Doctor !7MHPahvoGY — 11.4 years ago, 2 minutes later, 35 minutes after the original post[T] [B] #449,937
@OP
Not sure.
·Anonymous A (OP) — 11.4 years ago, 12 minutes later, 47 minutes after the original post[T] [B] #449,938
@449,936 (B)
Then post your proof.
·Anonymous B — 11.4 years ago, 58 seconds later, 48 minutes after the original post[T] [B] #449,939
@previous (A)
What will you give me if I post it?
+Anonymous D — 11.4 years ago, 37 seconds later, 49 minutes after the original post[T] [B] #449,940
@previous (B)
My cock in your mouth
·Anonymous B — 11.4 years ago, 56 seconds later, 50 minutes after the original post[T] [B] #449,941
@previous (D)
Post a pic of your cock first so I know if it's worth my time posting my proof.
·Anonymous A (OP) — 11.4 years ago, 3 minutes later, 53 minutes after the original post[T] [B] #449,942
·Anonymous B — 11.4 years ago, 2 minutes later, 55 minutes after the original post[T] [B] #449,943
@previous (A)
I can't see its cock.
+Anonymous E — 11.4 years ago, 8 minutes later, 1 hour after the original post[T] [B] #449,944
@previous (B)
Then you are a fucking nitwit city boy. That bird is a cock.
Best cooked as Coq a Vin.
·Anonymous B — 11.4 years ago, 16 minutes later, 1 hour after the original post[T] [B] #449,945
+On !Uvm54ORbmo — 11.4 years ago, 1 hour later, 3 hours after the original post[T] [B] #449,958
In this case does stranger mean everyone don't know that guy and that guy doesn't know any of the 44 guys
And does acquaintance mean everyone know that guy and that guy know every one of the 44 guys
·Anonymous A (OP) — 11.4 years ago, 3 minutes later, 3 hours after the original post[T] [B] #449,960
@previous (On !Uvm54ORbmo)
All the information you need to know, is in the posted problem.
·The Doctor !7MHPahvoGY — 11.4 years ago, 3 minutes later, 3 hours after the original post[T] [B] #449,963
@previous (A)
Nice unnecessary comma.
·Anonymous A (OP) — 11.4 years ago, 4 minutes later, 3 hours after the original post[T] [B] #449,964
@previous (The Doctor !7MHPahvoGY)
That may, or may not, help you, solve the problem.
·On !Uvm54ORbmo — 11.4 years ago, 8 minutes later, 3 hours after the original post[T] [B] #449,971
@449,960 (A)
Then I'll go for no
You can have PPL that's frequent on the news or internet
That most know him but he knows no one else
And it isn't difficult to find 45 internet celebrities
+Anonymous G — 11.4 years ago, 53 minutes later, 4 hours after the original post[T] [B] #449,984
Consider the 6° of separation idea. This theorem posits that there are 6 or fewer steps or degrees separating people from one another. 45/6 = 7.5. 5 broken cameras was a film about a dunecoon farmer peacefully resisting zionistfags. So this clearly means absolutely nothing. However, 666 = illuminati = 5 awkward mutual acquaintances in a 45 person gang bang with 7.5 niggers.
+FuckAlms !vX8K53rFBI — 11.4 years ago, 5 minutes later, 4 hours after the original post[T] [B] #449,986
@previous (G)
I think it is.
+Anonymous I — 11.4 years ago, 48 minutes later, 5 hours after the original post[T] [B] #449,989
@449,984 (G)
nice Morbidpost
·Anonymous I — 11.4 years ago, 2 minutes later, 5 hours after the original post[T] [B] #449,990
@OP
> Among 45 people, must there be 5 mutual strangers or 5 mutual acquaintances?
>
> Can you prove this to be true?
The answer is no, there not must be. Maybe there is one or the other or neither or both, so regardless, the situation described does not have to MUST be.
Start a new topic to continue this conversation.
Or browse the latest topics.