Topic: help whit math
+Anonymous A — 14.3 years ago #13,267
how resolve this : 2/3(x-1/3)-2*(x-1)=1/3
EVASION
(Edited 23 hours later by a moderator.)
+Anonymous B — 14.3 years ago, 4 minutes later[T] [B] #173,453
·Anonymous A (OP) — 14.3 years ago, 1 minute later, 5 minutes after the original post[T] [B] #173,454
o shi,
+Anonymous C — 14.3 years ago, 11 hours later, 11 hours after the original post[T] [B] #173,492
@OP
Distribute the fractions to their corresponding factors in parenthesis. Next FOIL the two parenthetical expressions. Subtract the 1/3 so the equation is equal to zero. At this point you can factor what you have or plug it in to the quadratic formula. Enjoy. Math rocks.
+FuckAlms !vX8K53rFBI — 14.3 years ago, 1 hour later, 13 hours after the original post[T] [B] #173,507
@previous (C)
How do discern equations from graphs?
+Motherfuckin' !xHGARYoak6 — 14.3 years ago, 8 hours later, 22 hours after the original post[T] [B] #173,536
This reminds me, im going back and doing my grade 12 math so i can finish up. Anyone have any suggestions on how to get back.into the swing of.doing math again? Websites or shit?
Its been 4 years since ive done this shit, pls help.
+Anonymous F — 14.3 years ago, 38 minutes later, 22 hours after the original post[T] [B] #173,538
@previous (Motherfuckin' !xHGARYoak6)
Find a grade 12 math textbook if you can.
·Anonymous C — 14.3 years ago, 1 hour later, 1 day after the original post[T] [B] #173,549
@173,507 (FuckAlms !vX8K53rFBI)
I need a little more context. As in, how do you look at a graph and be able to tell the equation?
·Anonymous C — 14.3 years ago, 1 minute later, 1 day after the original post[T] [B] #173,550
@173,536 (Motherfuckin' !xHGARYoak6)
http://www.khanacademy.org/
Pick your maths you want and you're golden.
·Anonymous F — 14.3 years ago, 8 minutes later, 1 day after the original post[T] [B] #173,552
@previous (C)
Faeggot. :)
·Anonymous C — 14.3 years ago, 2 minutes later, 1 day after the original post[T] [B] #173,554
+Anonymous G — 14.3 years ago, 14 hours later, 1 day after the original post[T] [B] #173,588
@173,536 (Motherfuckin' !xHGARYoak6)
take an online course and make heavy use of this website-
http://www.wolframalpha.com/ ·Motherfuckin' !xHGARYoak6 — 14.3 years ago, 29 minutes later, 1 day after the original post[T] [B] #173,589
@previous (G)
I'll look up a few things, and thanks for the site, it'll be useful to double check my work. I wish it would show steps so one would know where it went wrong in its calculations.
Thanks for the help
+Anonymous H — 14.3 years ago, 50 minutes later, 1 day after the original post[T] [B] #173,593
@previous (Motherfuckin' !xHGARYoak6)
Hey bro, it's anon C. Somehow my shit for reset. Anyways, I don't post here often but if you have any questions I'll help you with anything I can. Just post it ITT.
·Anonymous G — 14.3 years ago, 4 hours later, 1 day after the original post[T] [B] #173,606
@173,589 (Motherfuckin' !xHGARYoak6)
huh, it used to show every step along with the answer.
welp, im glad i got done with math before it stopped doing that
·FuckAlms !vX8K53rFBI — 14.3 years ago, 13 hours later, 2 days after the original post[T] [B] #173,662
@173,549 (C)
Yes. And the graphs are straight lines, no curves/logarithms.
I'd post a screenshot if I had one.
·Anonymous H — 14.3 years ago, 37 minutes later, 2 days after the original post[T] [B] #173,667
@previous (FuckAlms !vX8K53rFBI)
Straight lines as in completely vertical or completely horizontal are either y=some number or x=some number. Any horizontal line is of the y=some number variety and any vertical line is of the x=some number variety. This can be derived from the slope intercept form of graphing, which is y=mx+b. The "m" is generally the slope of the line and the "b" is where the line will cross the y-axis.
To determine an equation from a graph there are two approaches. If the line is completely vertical or horizontal and only crosses one axis then determine where it crosses and you have your answer of either y=a or x=b (depending on the line). For other linear examples you can use the slope intercept form as reference (y=mx+b). B will be where the line crosses the y-axis and m can be determined using the point-slope formula {(y-y1)/(x-x1) x cannot equal zero). To use the point slope pick two numbers where the line crosses the y-axis, subtract them and divide them by the difference of two numbers where the line crosses the x-axis. You then plug m and b into the y=mx+b formula and you have your answer.
You can check yourself by making a table, plugging in numbers for x and then getting an answer for y. After you have three or four coordinates, graph them and it should match the line from the original graph.
I hope that answered your question. If not let me know and I'll try to clear up any confusion I might have caused.
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